Integrand size = 27, antiderivative size = 153 \[ \int \cos ^6(c+d x) \sin (c+d x) (a+a \sin (c+d x))^2 \, dx=\frac {5 a^2 x}{64}-\frac {a^2 \cos ^7(c+d x)}{28 d}+\frac {5 a^2 \cos (c+d x) \sin (c+d x)}{64 d}+\frac {5 a^2 \cos ^3(c+d x) \sin (c+d x)}{96 d}+\frac {a^2 \cos ^5(c+d x) \sin (c+d x)}{24 d}-\frac {\cos ^7(c+d x) (a+a \sin (c+d x))^2}{9 d}-\frac {\cos ^7(c+d x) \left (a^2+a^2 \sin (c+d x)\right )}{36 d} \]
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Time = 0.13 (sec) , antiderivative size = 153, normalized size of antiderivative = 1.00, number of steps used = 7, number of rules used = 5, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.185, Rules used = {2939, 2757, 2748, 2715, 8} \[ \int \cos ^6(c+d x) \sin (c+d x) (a+a \sin (c+d x))^2 \, dx=-\frac {a^2 \cos ^7(c+d x)}{28 d}-\frac {\cos ^7(c+d x) \left (a^2 \sin (c+d x)+a^2\right )}{36 d}+\frac {a^2 \sin (c+d x) \cos ^5(c+d x)}{24 d}+\frac {5 a^2 \sin (c+d x) \cos ^3(c+d x)}{96 d}+\frac {5 a^2 \sin (c+d x) \cos (c+d x)}{64 d}+\frac {5 a^2 x}{64}-\frac {\cos ^7(c+d x) (a \sin (c+d x)+a)^2}{9 d} \]
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Rule 8
Rule 2715
Rule 2748
Rule 2757
Rule 2939
Rubi steps \begin{align*} \text {integral}& = -\frac {\cos ^7(c+d x) (a+a \sin (c+d x))^2}{9 d}+\frac {2}{9} \int \cos ^6(c+d x) (a+a \sin (c+d x))^2 \, dx \\ & = -\frac {\cos ^7(c+d x) (a+a \sin (c+d x))^2}{9 d}-\frac {\cos ^7(c+d x) \left (a^2+a^2 \sin (c+d x)\right )}{36 d}+\frac {1}{4} a \int \cos ^6(c+d x) (a+a \sin (c+d x)) \, dx \\ & = -\frac {a^2 \cos ^7(c+d x)}{28 d}-\frac {\cos ^7(c+d x) (a+a \sin (c+d x))^2}{9 d}-\frac {\cos ^7(c+d x) \left (a^2+a^2 \sin (c+d x)\right )}{36 d}+\frac {1}{4} a^2 \int \cos ^6(c+d x) \, dx \\ & = -\frac {a^2 \cos ^7(c+d x)}{28 d}+\frac {a^2 \cos ^5(c+d x) \sin (c+d x)}{24 d}-\frac {\cos ^7(c+d x) (a+a \sin (c+d x))^2}{9 d}-\frac {\cos ^7(c+d x) \left (a^2+a^2 \sin (c+d x)\right )}{36 d}+\frac {1}{24} \left (5 a^2\right ) \int \cos ^4(c+d x) \, dx \\ & = -\frac {a^2 \cos ^7(c+d x)}{28 d}+\frac {5 a^2 \cos ^3(c+d x) \sin (c+d x)}{96 d}+\frac {a^2 \cos ^5(c+d x) \sin (c+d x)}{24 d}-\frac {\cos ^7(c+d x) (a+a \sin (c+d x))^2}{9 d}-\frac {\cos ^7(c+d x) \left (a^2+a^2 \sin (c+d x)\right )}{36 d}+\frac {1}{32} \left (5 a^2\right ) \int \cos ^2(c+d x) \, dx \\ & = -\frac {a^2 \cos ^7(c+d x)}{28 d}+\frac {5 a^2 \cos (c+d x) \sin (c+d x)}{64 d}+\frac {5 a^2 \cos ^3(c+d x) \sin (c+d x)}{96 d}+\frac {a^2 \cos ^5(c+d x) \sin (c+d x)}{24 d}-\frac {\cos ^7(c+d x) (a+a \sin (c+d x))^2}{9 d}-\frac {\cos ^7(c+d x) \left (a^2+a^2 \sin (c+d x)\right )}{36 d}+\frac {1}{64} \left (5 a^2\right ) \int 1 \, dx \\ & = \frac {5 a^2 x}{64}-\frac {a^2 \cos ^7(c+d x)}{28 d}+\frac {5 a^2 \cos (c+d x) \sin (c+d x)}{64 d}+\frac {5 a^2 \cos ^3(c+d x) \sin (c+d x)}{96 d}+\frac {a^2 \cos ^5(c+d x) \sin (c+d x)}{24 d}-\frac {\cos ^7(c+d x) (a+a \sin (c+d x))^2}{9 d}-\frac {\cos ^7(c+d x) \left (a^2+a^2 \sin (c+d x)\right )}{36 d} \\ \end{align*}
Time = 0.29 (sec) , antiderivative size = 106, normalized size of antiderivative = 0.69 \[ \int \cos ^6(c+d x) \sin (c+d x) (a+a \sin (c+d x))^2 \, dx=\frac {a^2 (2520 c+2520 d x-3276 \cos (c+d x)-1848 \cos (3 (c+d x))-504 \cos (5 (c+d x))-18 \cos (7 (c+d x))+14 \cos (9 (c+d x))+1008 \sin (2 (c+d x))-504 \sin (4 (c+d x))-336 \sin (6 (c+d x))-63 \sin (8 (c+d x)))}{32256 d} \]
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Time = 0.62 (sec) , antiderivative size = 111, normalized size of antiderivative = 0.73
method | result | size |
parallelrisch | \(-\frac {a^{2} \left (-2520 d x +3276 \cos \left (d x +c \right )+336 \sin \left (6 d x +6 c \right )+18 \cos \left (7 d x +7 c \right )+504 \sin \left (4 d x +4 c \right )+63 \sin \left (8 d x +8 c \right )-1008 \sin \left (2 d x +2 c \right )+504 \cos \left (5 d x +5 c \right )+1848 \cos \left (3 d x +3 c \right )-14 \cos \left (9 d x +9 c \right )+5632\right )}{32256 d}\) | \(111\) |
derivativedivides | \(\frac {a^{2} \left (-\frac {\left (\cos ^{7}\left (d x +c \right )\right ) \left (\sin ^{2}\left (d x +c \right )\right )}{9}-\frac {2 \left (\cos ^{7}\left (d x +c \right )\right )}{63}\right )+2 a^{2} \left (-\frac {\left (\cos ^{7}\left (d x +c \right )\right ) \sin \left (d x +c \right )}{8}+\frac {\left (\cos ^{5}\left (d x +c \right )+\frac {5 \left (\cos ^{3}\left (d x +c \right )\right )}{4}+\frac {15 \cos \left (d x +c \right )}{8}\right ) \sin \left (d x +c \right )}{48}+\frac {5 d x}{128}+\frac {5 c}{128}\right )-\frac {a^{2} \left (\cos ^{7}\left (d x +c \right )\right )}{7}}{d}\) | \(116\) |
default | \(\frac {a^{2} \left (-\frac {\left (\cos ^{7}\left (d x +c \right )\right ) \left (\sin ^{2}\left (d x +c \right )\right )}{9}-\frac {2 \left (\cos ^{7}\left (d x +c \right )\right )}{63}\right )+2 a^{2} \left (-\frac {\left (\cos ^{7}\left (d x +c \right )\right ) \sin \left (d x +c \right )}{8}+\frac {\left (\cos ^{5}\left (d x +c \right )+\frac {5 \left (\cos ^{3}\left (d x +c \right )\right )}{4}+\frac {15 \cos \left (d x +c \right )}{8}\right ) \sin \left (d x +c \right )}{48}+\frac {5 d x}{128}+\frac {5 c}{128}\right )-\frac {a^{2} \left (\cos ^{7}\left (d x +c \right )\right )}{7}}{d}\) | \(116\) |
risch | \(\frac {5 a^{2} x}{64}-\frac {13 a^{2} \cos \left (d x +c \right )}{128 d}+\frac {a^{2} \cos \left (9 d x +9 c \right )}{2304 d}-\frac {a^{2} \sin \left (8 d x +8 c \right )}{512 d}-\frac {a^{2} \cos \left (7 d x +7 c \right )}{1792 d}-\frac {a^{2} \sin \left (6 d x +6 c \right )}{96 d}-\frac {a^{2} \cos \left (5 d x +5 c \right )}{64 d}-\frac {a^{2} \sin \left (4 d x +4 c \right )}{64 d}-\frac {11 a^{2} \cos \left (3 d x +3 c \right )}{192 d}+\frac {a^{2} \sin \left (2 d x +2 c \right )}{32 d}\) | \(158\) |
norman | \(\frac {-\frac {8 a^{2} \left (\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{7 d}-\frac {16 a^{2} \left (\tan ^{12}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{3 d}+\frac {5 a^{2} x}{64}-\frac {22 a^{2}}{63 d}-\frac {145 a^{2} \left (\tan ^{11}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{16 d}-\frac {5 a^{2} \tan \left (\frac {d x}{2}+\frac {c}{2}\right )}{32 d}+\frac {83 a^{2} \left (\tan ^{13}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{16 d}+\frac {5 a^{2} x \left (\tan ^{18}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{64}-\frac {40 a^{2} \left (\tan ^{10}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{d}+\frac {145 a^{2} \left (\tan ^{7}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{16 d}-\frac {32 a^{2} \left (\tan ^{4}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{7 d}-\frac {24 a^{2} \left (\tan ^{6}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{d}+\frac {191 a^{2} \left (\tan ^{3}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{48 d}-\frac {83 a^{2} \left (\tan ^{5}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{16 d}-\frac {4 a^{2} \left (\tan ^{8}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{d}-\frac {8 a^{2} \left (\tan ^{14}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{d}-\frac {2 a^{2} \left (\tan ^{16}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{d}-\frac {191 a^{2} \left (\tan ^{15}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{48 d}+\frac {5 a^{2} \left (\tan ^{17}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{32 d}+\frac {315 a^{2} x \left (\tan ^{8}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{32}+\frac {45 a^{2} x \left (\tan ^{4}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{16}+\frac {105 a^{2} x \left (\tan ^{12}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{16}+\frac {45 a^{2} x \left (\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{64}+\frac {315 a^{2} x \left (\tan ^{10}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{32}+\frac {105 a^{2} x \left (\tan ^{6}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{16}+\frac {45 a^{2} x \left (\tan ^{14}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{16}+\frac {45 a^{2} x \left (\tan ^{16}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{64}}{\left (1+\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )^{9}}\) | \(487\) |
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Time = 0.27 (sec) , antiderivative size = 98, normalized size of antiderivative = 0.64 \[ \int \cos ^6(c+d x) \sin (c+d x) (a+a \sin (c+d x))^2 \, dx=\frac {448 \, a^{2} \cos \left (d x + c\right )^{9} - 1152 \, a^{2} \cos \left (d x + c\right )^{7} + 315 \, a^{2} d x - 21 \, {\left (48 \, a^{2} \cos \left (d x + c\right )^{7} - 8 \, a^{2} \cos \left (d x + c\right )^{5} - 10 \, a^{2} \cos \left (d x + c\right )^{3} - 15 \, a^{2} \cos \left (d x + c\right )\right )} \sin \left (d x + c\right )}{4032 \, d} \]
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Leaf count of result is larger than twice the leaf count of optimal. 282 vs. \(2 (139) = 278\).
Time = 0.92 (sec) , antiderivative size = 282, normalized size of antiderivative = 1.84 \[ \int \cos ^6(c+d x) \sin (c+d x) (a+a \sin (c+d x))^2 \, dx=\begin {cases} \frac {5 a^{2} x \sin ^{8}{\left (c + d x \right )}}{64} + \frac {5 a^{2} x \sin ^{6}{\left (c + d x \right )} \cos ^{2}{\left (c + d x \right )}}{16} + \frac {15 a^{2} x \sin ^{4}{\left (c + d x \right )} \cos ^{4}{\left (c + d x \right )}}{32} + \frac {5 a^{2} x \sin ^{2}{\left (c + d x \right )} \cos ^{6}{\left (c + d x \right )}}{16} + \frac {5 a^{2} x \cos ^{8}{\left (c + d x \right )}}{64} + \frac {5 a^{2} \sin ^{7}{\left (c + d x \right )} \cos {\left (c + d x \right )}}{64 d} + \frac {55 a^{2} \sin ^{5}{\left (c + d x \right )} \cos ^{3}{\left (c + d x \right )}}{192 d} + \frac {73 a^{2} \sin ^{3}{\left (c + d x \right )} \cos ^{5}{\left (c + d x \right )}}{192 d} - \frac {a^{2} \sin ^{2}{\left (c + d x \right )} \cos ^{7}{\left (c + d x \right )}}{7 d} - \frac {5 a^{2} \sin {\left (c + d x \right )} \cos ^{7}{\left (c + d x \right )}}{64 d} - \frac {2 a^{2} \cos ^{9}{\left (c + d x \right )}}{63 d} - \frac {a^{2} \cos ^{7}{\left (c + d x \right )}}{7 d} & \text {for}\: d \neq 0 \\x \left (a \sin {\left (c \right )} + a\right )^{2} \sin {\left (c \right )} \cos ^{6}{\left (c \right )} & \text {otherwise} \end {cases} \]
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Time = 0.22 (sec) , antiderivative size = 93, normalized size of antiderivative = 0.61 \[ \int \cos ^6(c+d x) \sin (c+d x) (a+a \sin (c+d x))^2 \, dx=-\frac {4608 \, a^{2} \cos \left (d x + c\right )^{7} - 512 \, {\left (7 \, \cos \left (d x + c\right )^{9} - 9 \, \cos \left (d x + c\right )^{7}\right )} a^{2} - 21 \, {\left (64 \, \sin \left (2 \, d x + 2 \, c\right )^{3} + 120 \, d x + 120 \, c - 3 \, \sin \left (8 \, d x + 8 \, c\right ) - 24 \, \sin \left (4 \, d x + 4 \, c\right )\right )} a^{2}}{32256 \, d} \]
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Time = 0.37 (sec) , antiderivative size = 157, normalized size of antiderivative = 1.03 \[ \int \cos ^6(c+d x) \sin (c+d x) (a+a \sin (c+d x))^2 \, dx=\frac {5}{64} \, a^{2} x + \frac {a^{2} \cos \left (9 \, d x + 9 \, c\right )}{2304 \, d} - \frac {a^{2} \cos \left (7 \, d x + 7 \, c\right )}{1792 \, d} - \frac {a^{2} \cos \left (5 \, d x + 5 \, c\right )}{64 \, d} - \frac {11 \, a^{2} \cos \left (3 \, d x + 3 \, c\right )}{192 \, d} - \frac {13 \, a^{2} \cos \left (d x + c\right )}{128 \, d} - \frac {a^{2} \sin \left (8 \, d x + 8 \, c\right )}{512 \, d} - \frac {a^{2} \sin \left (6 \, d x + 6 \, c\right )}{96 \, d} - \frac {a^{2} \sin \left (4 \, d x + 4 \, c\right )}{64 \, d} + \frac {a^{2} \sin \left (2 \, d x + 2 \, c\right )}{32 \, d} \]
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Time = 11.75 (sec) , antiderivative size = 501, normalized size of antiderivative = 3.27 \[ \int \cos ^6(c+d x) \sin (c+d x) (a+a \sin (c+d x))^2 \, dx=\frac {5\,a^2\,x}{64}-\frac {\frac {83\,a^2\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^5}{16}-\frac {191\,a^2\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^3}{48}-\frac {145\,a^2\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^7}{16}+\frac {145\,a^2\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^{11}}{16}-\frac {83\,a^2\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^{13}}{16}+\frac {191\,a^2\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^{15}}{48}-\frac {5\,a^2\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^{17}}{32}+\frac {a^2\,\left (315\,c+315\,d\,x\right )}{4032}-\frac {a^2\,\left (315\,c+315\,d\,x-1408\right )}{4032}+{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^2\,\left (\frac {a^2\,\left (315\,c+315\,d\,x\right )}{448}-\frac {a^2\,\left (2835\,c+2835\,d\,x-4608\right )}{4032}\right )+{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^{16}\,\left (\frac {a^2\,\left (315\,c+315\,d\,x\right )}{448}-\frac {a^2\,\left (2835\,c+2835\,d\,x-8064\right )}{4032}\right )+{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^4\,\left (\frac {a^2\,\left (315\,c+315\,d\,x\right )}{112}-\frac {a^2\,\left (11340\,c+11340\,d\,x-18432\right )}{4032}\right )+{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^{14}\,\left (\frac {a^2\,\left (315\,c+315\,d\,x\right )}{112}-\frac {a^2\,\left (11340\,c+11340\,d\,x-32256\right )}{4032}\right )+{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^{12}\,\left (\frac {a^2\,\left (315\,c+315\,d\,x\right )}{48}-\frac {a^2\,\left (26460\,c+26460\,d\,x-21504\right )}{4032}\right )+{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^8\,\left (\frac {a^2\,\left (315\,c+315\,d\,x\right )}{32}-\frac {a^2\,\left (39690\,c+39690\,d\,x-16128\right )}{4032}\right )+{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^6\,\left (\frac {a^2\,\left (315\,c+315\,d\,x\right )}{48}-\frac {a^2\,\left (26460\,c+26460\,d\,x-96768\right )}{4032}\right )+{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^{10}\,\left (\frac {a^2\,\left (315\,c+315\,d\,x\right )}{32}-\frac {a^2\,\left (39690\,c+39690\,d\,x-161280\right )}{4032}\right )+\frac {5\,a^2\,\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}{32}}{d\,{\left ({\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^2+1\right )}^9} \]
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